What are the solutions to the equation 2x+5= 3/5 x^2 ?

The solutions to the equation 2x+5= 3/5 x^2 are x=5,x=-5/3

Find the zeros of 2x+5= 3/5 x^2

The zeros of 2x+5= 3/5 x^2 are x=5,x=-5/3

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2 x + 5 = \frac{3}{5} x^{2}

x = 5, x = - \frac{5}{3}

Decimal Notation

x = 5, x = - 1.66666 \dots

Solution steps

2 x + 5 = \frac{3}{5} x^{2}

Multiply both sides by

5

10 x + 25 = 3 x^{2}

Switch sides

3 x^{2} = 10 x + 25

Move

25

to the left side

3 x^{2} - 25 = 10 x

Move

10 x

to the left side

3 x^{2} - 25 - 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 10 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 3 ( - 25 )}{2 \cdot 3}

(- 10)^{2} - 4 \cdot 3 (- 25) = 20

x_{1, 2} = \frac{- ( - 10 ) \pm 20}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 20}{2 \cdot 3}, x_{2} = \frac{- ( - 10 ) - 20}{2 \cdot 3}

x = \frac{- ( - 10 ) + 20}{2 \cdot 3} : 5

x = \frac{- ( - 10 ) - 20}{2 \cdot 3} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = 5, x = - \frac{5}{3}

2 x^{2} - 18 = 0

(5^{3})^{2}

(3 x - 5)^{2} = 19

\frac{x ^{2}}{3 y} + 4 y

\frac{3}{8} \cdot \frac{1}{3}

What are the solutions to the equation 2x+5= 3/5 x^2 ?
The solutions to the equation 2x+5= 3/5 x^2 are x=5,x=-5/3
Find the zeros of 2x+5= 3/5 x^2
The zeros of 2x+5= 3/5 x^2 are x=5,x=-5/3