What are the solutions to the equation 3=x^2+2x+1 ?

The solutions to the equation 3=x^2+2x+1 are x=-1+sqrt(3),x=-1-sqrt(3)

Find the zeros of 3=x^2+2x+1

The zeros of 3=x^2+2x+1 are x=-1+sqrt(3),x=-1-sqrt(3)

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3 = x^{2} + 2 x + 1

x = - 1 + 3, x = - 1 - 3

Decimal Notation

x = 0.73205 \dots, x = - 2.73205 \dots

Solution steps

3 = x^{2} + 2 x + 1

Switch sides

x^{2} + 2 x + 1 = 3

Move

3

to the left side

x^{2} + 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 2) = 23

x_{1, 2} = \frac{- 2 \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 3}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 3}{2 \cdot 1}

x = \frac{- 2 + 2 3}{2 \cdot 1} : - 1 + 3

x = \frac{- 2 - 2 3}{2 \cdot 1} : - 1 - 3

The solutions to the quadratic equation are:

x = - 1 + 3, x = - 1 - 3

40 = x^{2} - 6 x

x^{2} - 2 x = x + 6

- x^{2} - 5 x - 17 = 0

9 x^{2} - 2 x = 10 x + 25 - 12 x

2 x (2 x - 5) + 18 = x (7 - x) - 12

What are the solutions to the equation 3=x^2+2x+1 ?
The solutions to the equation 3=x^2+2x+1 are x=-1+sqrt(3),x=-1-sqrt(3)
Find the zeros of 3=x^2+2x+1
The zeros of 3=x^2+2x+1 are x=-1+sqrt(3),x=-1-sqrt(3)