What are the solutions to the equation 40=x^2-6x ?

The solutions to the equation 40=x^2-6x are x=10,x=-4

Find the zeros of 40=x^2-6x

The zeros of 40=x^2-6x are x=10,x=-4

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40 = x^{2} - 6 x

x = 10, x = - 4

Solution steps

40 = x^{2} - 6 x

Switch sides

x^{2} - 6 x = 40

Move

40

to the left side

x^{2} - 6 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 40) = 14

x_{1, 2} = \frac{- ( - 6 ) \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 14}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 14}{2 \cdot 1}

x = \frac{- ( - 6 ) + 14}{2 \cdot 1} : 10

x = \frac{- ( - 6 ) - 14}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 10, x = - 4

x^{2} - 2 x = x + 6

- x^{2} - 5 x - 17 = 0

9 x^{2} - 2 x = 10 x + 25 - 12 x

2 x (2 x - 5) + 18 = x (7 - x) - 12

- x^{2} + x = - 2

What are the solutions to the equation 40=x^2-6x ?
The solutions to the equation 40=x^2-6x are x=10,x=-4
Find the zeros of 40=x^2-6x
The zeros of 40=x^2-6x are x=10,x=-4