What are the solutions to the equation -x^2+x=-2 ?

The solutions to the equation -x^2+x=-2 are x=-1,x=2

Find the zeros of -x^2+x=-2

The zeros of -x^2+x=-2 are x=-1,x=2

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- x^{2} + x = - 2

x = - 1, x = 2

Solution steps

- x^{2} + x = - 2

Move

2

to the left side

- x^{2} + x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 2}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 2 = 3

x_{1, 2} = \frac{- 1 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 3}{2 ( - 1 )}, x_{2} = \frac{- 1 - 3}{2 ( - 1 )}

x = \frac{- 1 + 3}{2 ( - 1 )} : - 1

x = \frac{- 1 - 3}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = - 1, x = 2

3 x^{2} + x - 10 = 0

(x + 8)^{2} = 121

5 x^{2} - 40 x + 35 = 0

y, x = 2 y^{2}

x^{2} + 4 x - 32

What are the solutions to the equation -x^2+x=-2 ?
The solutions to the equation -x^2+x=-2 are x=-1,x=2
Find the zeros of -x^2+x=-2
The zeros of -x^2+x=-2 are x=-1,x=2