What are the solutions to the equation 5x^2-40x+35=0 ?

The solutions to the equation 5x^2-40x+35=0 are x=7,x=1

Find the zeros of 5x^2-40x+35=0

The zeros of 5x^2-40x+35=0 are x=7,x=1

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5 x^{2} - 40 x + 35 = 0

x = 7, x = 1

Solution steps

5 x^{2} - 40 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 5 \cdot 35}{2 \cdot 5}

(- 40)^{2} - 4 \cdot 5 \cdot 35 = 30

x_{1, 2} = \frac{- ( - 40 ) \pm 30}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 30}{2 \cdot 5}, x_{2} = \frac{- ( - 40 ) - 30}{2 \cdot 5}

x = \frac{- ( - 40 ) + 30}{2 \cdot 5} : 7

x = \frac{- ( - 40 ) - 30}{2 \cdot 5} : 1

The solutions to the quadratic equation are:

x = 7, x = 1

y, x = 2 y^{2}

x^{2} + 4 x - 32

x^{2} - 3 x - 5 = 0

9 x^{2} - 24 x - 24 = 0

14 x + 3 = - 8 x^{2}

What are the solutions to the equation 5x^2-40x+35=0 ?
The solutions to the equation 5x^2-40x+35=0 are x=7,x=1
Find the zeros of 5x^2-40x+35=0
The zeros of 5x^2-40x+35=0 are x=7,x=1