What are the solutions to the equation -8x-4x^2=14 ?

The solutions to the equation -8x-4x^2=14 are x=-1-isqrt(5/2),x=-1+isqrt(5/2)

Find the zeros of -8x-4x^2=14

The zeros of -8x-4x^2=14 are x=-1-isqrt(5/2),x=-1+isqrt(5/2)

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- 8 x - 4 x^{2} = 14

x = - 1 - i \frac{5}{2}, x = - 1 + i \frac{5}{2}

Solution steps

- 8 x - 4 x^{2} = 14

Move

14

to the left side

- 8 x - 4 x^{2} - 14 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} - 8 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 4 ) ( - 14 )}{2 ( - 4 )}

Simplify

(- 8)^{2} - 4 (- 4) (- 14) : 410 i

x_{1, 2} = \frac{- ( - 8 ) \pm 4 10 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 10 i}{2 ( - 4 )}, x_{2} = \frac{- ( - 8 ) - 4 10 i}{2 ( - 4 )}

x = \frac{- ( - 8 ) + 4 10 i}{2 ( - 4 )} : - 1 - i \frac{5}{2}

x = \frac{- ( - 8 ) - 4 10 i}{2 ( - 4 )} : - 1 + i \frac{5}{2}

The solutions to the quadratic equation are:

x = - 1 - i \frac{5}{2}, x = - 1 + i \frac{5}{2}

4 (x + 5)^{2} = - 64

2 x^{2} + 4 x + 18 = 0

5^{2} + b^{2} = 1 2^{2}

x^{2} + 3 x - 6 = 8

d^{2} + d - 72 = 0

What are the solutions to the equation -8x-4x^2=14 ?
The solutions to the equation -8x-4x^2=14 are x=-1-isqrt(5/2),x=-1+isqrt(5/2)
Find the zeros of -8x-4x^2=14
The zeros of -8x-4x^2=14 are x=-1-isqrt(5/2),x=-1+isqrt(5/2)