What are the solutions to the equation x^2+24x-144=0 ?

The solutions to the equation x^2+24x-144=0 are x=12(sqrt(2)-1),x=-12(1+sqrt(2))

Find the zeros of x^2+24x-144=0

The zeros of x^2+24x-144=0 are x=12(sqrt(2)-1),x=-12(1+sqrt(2))

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x^{2} + 24 x - 144 = 0

x = 12 (2 - 1), x = - 12 (1 + 2)

Decimal Notation

x = 4.97056 \dots, x = - 28.97056 \dots

Solution steps

x^{2} + 24 x - 144 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 1 \cdot ( - 144 )}{2 \cdot 1}

2 4^{2} - 4 \cdot 1 \cdot (- 144) = 242

x_{1, 2} = \frac{- 24 \pm 24 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 24 + 24 2}{2 \cdot 1}, x_{2} = \frac{- 24 - 24 2}{2 \cdot 1}

x = \frac{- 24 + 24 2}{2 \cdot 1} : 12 (2 - 1)

x = \frac{- 24 - 24 2}{2 \cdot 1} : - 12 (1 + 2)

The solutions to the quadratic equation are:

x = 12 (2 - 1), x = - 12 (1 + 2)

2 x = 4 x^{2} - 5 x + 50

v^{2} + 10 v + 16 = 0

4 x^{2} - 5 x - 21 = 0

n^{2} - 9 = 0

4 x^{2} + x = - 3

What are the solutions to the equation x^2+24x-144=0 ?
The solutions to the equation x^2+24x-144=0 are x=12(sqrt(2)-1),x=-12(1+sqrt(2))
Find the zeros of x^2+24x-144=0
The zeros of x^2+24x-144=0 are x=12(sqrt(2)-1),x=-12(1+sqrt(2))