What are the solutions to the equation v^2+10v+16=0 ?

The solutions to the equation v^2+10v+16=0 are v=-2,v=-8

Find the zeros of v^2+10v+16=0

The zeros of v^2+10v+16=0 are v=-2,v=-8

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v^{2} + 10 v + 16 = 0

v = - 2, v = - 8

Solution steps

v^{2} + 10 v + 16 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 16 = 6

v_{1, 2} = \frac{- 10 \pm 6}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 10 + 6}{2 \cdot 1}, v_{2} = \frac{- 10 - 6}{2 \cdot 1}

v = \frac{- 10 + 6}{2 \cdot 1} : - 2

v = \frac{- 10 - 6}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

v = - 2, v = - 8

4 x^{2} - 5 x - 21 = 0

n^{2} - 9 = 0

4 x^{2} + x = - 3

(x - 3)^{2} + 7 = 23

0 = 3 x^{2} + 2 x + 0.5

What are the solutions to the equation v^2+10v+16=0 ?
The solutions to the equation v^2+10v+16=0 are v=-2,v=-8
Find the zeros of v^2+10v+16=0
The zeros of v^2+10v+16=0 are v=-2,v=-8