What are the solutions to the equation 0=3x^2+2x+0.5 ?

The solutions to the equation 0=3x^2+2x+0.5 are x=-1/3+i(sqrt(2))/6 ,x=-1/3-i(sqrt(2))/6

Find the zeros of 0=3x^2+2x+0.5

The zeros of 0=3x^2+2x+0.5 are x=-1/3+i(sqrt(2))/6 ,x=-1/3-i(sqrt(2))/6

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0 = 3 x^{2} + 2 x + 0.5

x = - \frac{1}{3} + i \frac{2}{6}, x = - \frac{1}{3} - i \frac{2}{6}

Solution steps

0 = 3 x^{2} + 2 x + 0.5

Multiply both sides by

10

0 = 30 x^{2} + 20 x + 5

Switch sides

30 x^{2} + 20 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 30 \cdot 5}{2 \cdot 30}

Simplify

2 0^{2} - 4 \cdot 30 \cdot 5 : 102 i

x_{1, 2} = \frac{- 20 \pm 10 2 i}{2 \cdot 30}

Separate the solutions

x_{1} = \frac{- 20 + 10 2 i}{2 \cdot 30}, x_{2} = \frac{- 20 - 10 2 i}{2 \cdot 30}

x = \frac{- 20 + 10 2 i}{2 \cdot 30} : - \frac{1}{3} + i \frac{2}{6}

x = \frac{- 20 - 10 2 i}{2 \cdot 30} : - \frac{1}{3} - i \frac{2}{6}

The solutions to the quadratic equation are:

x = - \frac{1}{3} + i \frac{2}{6}, x = - \frac{1}{3} - i \frac{2}{6}

3 a^{2} - 108 = 0

z^{2} + 64 = 0

5 x^{2} + 7 = 507

x^{2} - 16 x = - 61

4 x^{2} - 32 x + 60 = 0

What are the solutions to the equation 0=3x^2+2x+0.5 ?
The solutions to the equation 0=3x^2+2x+0.5 are x=-1/3+i(sqrt(2))/6 ,x=-1/3-i(sqrt(2))/6
Find the zeros of 0=3x^2+2x+0.5
The zeros of 0=3x^2+2x+0.5 are x=-1/3+i(sqrt(2))/6 ,x=-1/3-i(sqrt(2))/6