What are the solutions to the equation 5x^2+7=507 ?

The solutions to the equation 5x^2+7=507 are x=10,x=-10

Find the zeros of 5x^2+7=507

The zeros of 5x^2+7=507 are x=10,x=-10

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5 x^{2} + 7 = 507

x = 10, x = - 10

Solution steps

5 x^{2} + 7 = 507

Move

7

to the right side

5 x^{2} = 500

Divide both sides by

5

x^{2} = 100

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 100, x = - 100

100 = 10

- 100 = - 10

x = 10, x = - 10

x^{2} - 16 x = - 61

4 x^{2} - 32 x + 60 = 0

16 x^{2} + 7 = 0

(x - 4)^{2} - 5 (x - 4) = 24

a^{2} - 2 a - 8 = 0

What are the solutions to the equation 5x^2+7=507 ?
The solutions to the equation 5x^2+7=507 are x=10,x=-10
Find the zeros of 5x^2+7=507
The zeros of 5x^2+7=507 are x=10,x=-10