What are the solutions to the equation 16x^2+7=0 ?

The solutions to the equation 16x^2+7=0 are x=(sqrt(7))/4 i,x=-(sqrt(7))/4 i

Find the zeros of 16x^2+7=0

The zeros of 16x^2+7=0 are x=(sqrt(7))/4 i,x=-(sqrt(7))/4 i

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16 x^{2} + 7 = 0

x = \frac{7}{4} i, x = - \frac{7}{4} i

Solution steps

16 x^{2} + 7 = 0

Move

7

to the right side

16 x^{2} = - 7

Divide both sides by

16

x^{2} = - \frac{7}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{7}{16}, x = - - \frac{7}{16}

- \frac{7}{16} = \frac{7}{4} i

- - \frac{7}{16} = - \frac{7}{4} i

x = \frac{7}{4} i, x = - \frac{7}{4} i

(x - 4)^{2} - 5 (x - 4) = 24

a^{2} - 2 a - 8 = 0

- 20 = 10 t - \frac{9.81 t ^{2}}{2}

30 + 19 x - 4 x^{2} = 0

x, b x = a x^{2} + c

What are the solutions to the equation 16x^2+7=0 ?
The solutions to the equation 16x^2+7=0 are x=(sqrt(7))/4 i,x=-(sqrt(7))/4 i
Find the zeros of 16x^2+7=0
The zeros of 16x^2+7=0 are x=(sqrt(7))/4 i,x=-(sqrt(7))/4 i