What are the solutions to the equation 30+19x-4x^2=0 ?

The solutions to the equation 30+19x-4x^2=0 are x=-5/4 ,x=6

Find the zeros of 30+19x-4x^2=0

The zeros of 30+19x-4x^2=0 are x=-5/4 ,x=6

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30 + 19 x - 4 x^{2} = 0

x = - \frac{5}{4}, x = 6

Decimal Notation

x = - 1.25, x = 6

Solution steps

30 + 19 x - 4 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} + 19 x + 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 ( - 4 ) \cdot 30}{2 ( - 4 )}

1 9^{2} - 4 (- 4) \cdot 30 = 29

x_{1, 2} = \frac{- 19 \pm 29}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 19 + 29}{2 ( - 4 )}, x_{2} = \frac{- 19 - 29}{2 ( - 4 )}

x = \frac{- 19 + 29}{2 ( - 4 )} : - \frac{5}{4}

x = \frac{- 19 - 29}{2 ( - 4 )} : 6

The solutions to the quadratic equation are:

x = - \frac{5}{4}, x = 6

x, b x = a x^{2} + c

5 x - 6 = - 2 x^{2}

3 (- 2 r - 5) + 4 = r^{2} + 2

(x + 8) (2 x - 3) = 0

8 x^{2} + 2 x - 12 x - 3 = 0

What are the solutions to the equation 30+19x-4x^2=0 ?
The solutions to the equation 30+19x-4x^2=0 are x=-5/4 ,x=6
Find the zeros of 30+19x-4x^2=0
The zeros of 30+19x-4x^2=0 are x=-5/4 ,x=6