What are the solutions to the equation (x+8)(2x-3)=0 ?

The solutions to the equation (x+8)(2x-3)=0 are x=-8,x= 3/2

Find the zeros of (x+8)(2x-3)=0

The zeros of (x+8)(2x-3)=0 are x=-8,x= 3/2

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(x + 8) (2 x - 3) = 0

x = - 8, x = \frac{3}{2}

Decimal Notation

x = - 8, x = 1.5

Solution steps

(x + 8) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 8 = 0 or 2 x - 3 = 0

Solve

x + 8 = 0 : x = - 8

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions to the quadratic equation are:

x = - 8, x = \frac{3}{2}

8 x^{2} + 2 x - 12 x - 3 = 0

7 x^{2} = 9 x + 1

n^{2} - 9 n + 10 = 0

A = 2 π r^{2} + 2 π r h, r

x, f = x^{2} + m x + m

What are the solutions to the equation (x+8)(2x-3)=0 ?
The solutions to the equation (x+8)(2x-3)=0 are x=-8,x= 3/2
Find the zeros of (x+8)(2x-3)=0
The zeros of (x+8)(2x-3)=0 are x=-8,x= 3/2