What are the solutions to the equation 7x^2=9x+1 ?

The solutions to the equation 7x^2=9x+1 are x=(9+sqrt(109))/(14),x=(9-sqrt(109))/(14)

Find the zeros of 7x^2=9x+1

The zeros of 7x^2=9x+1 are x=(9+sqrt(109))/(14),x=(9-sqrt(109))/(14)

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7 x^{2} = 9 x + 1

x = \frac{9 + 109}{14}, x = \frac{9 - 109}{14}

Decimal Notation

x = 1.38859 \dots, x = - 0.10287 \dots

Solution steps

7 x^{2} = 9 x + 1

Move

1

to the left side

7 x^{2} - 1 = 9 x

Move

9 x

to the left side

7 x^{2} - 1 - 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

7 x^{2} - 9 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 7 ( - 1 )}{2 \cdot 7}

(- 9)^{2} - 4 \cdot 7 (- 1) = 109

x_{1, 2} = \frac{- ( - 9 ) \pm 109}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 109}{2 \cdot 7}, x_{2} = \frac{- ( - 9 ) - 109}{2 \cdot 7}

x = \frac{- ( - 9 ) + 109}{2 \cdot 7} : \frac{9 + 109}{14}

x = \frac{- ( - 9 ) - 109}{2 \cdot 7} : \frac{9 - 109}{14}

The solutions to the quadratic equation are:

x = \frac{9 + 109}{14}, x = \frac{9 - 109}{14}

n^{2} - 9 n + 10 = 0

A = 2 π r^{2} + 2 π r h, r

x, f = x^{2} + m x + m

x (2 x - 5) = - 3

(x + \frac{1}{2}) (x - 2) = 0

What are the solutions to the equation 7x^2=9x+1 ?
The solutions to the equation 7x^2=9x+1 are x=(9+sqrt(109))/(14),x=(9-sqrt(109))/(14)
Find the zeros of 7x^2=9x+1
The zeros of 7x^2=9x+1 are x=(9+sqrt(109))/(14),x=(9-sqrt(109))/(14)