What are the solutions to the equation x(2x-5)=-3 ?

The solutions to the equation x(2x-5)=-3 are x= 3/2 ,x=1

Find the zeros of x(2x-5)=-3

The zeros of x(2x-5)=-3 are x= 3/2 ,x=1

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x (2 x - 5) = - 3

x = \frac{3}{2}, x = 1

Decimal Notation

x = 1.5, x = 1

Solution steps

x (2 x - 5) = - 3

Expand

x (2 x - 5) : 2 x^{2} - 5 x

2 x^{2} - 5 x = - 3

Move

3

to the left side

2 x^{2} - 5 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 \cdot 3 = 1

x_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 2}

x = \frac{- ( - 5 ) + 1}{2 \cdot 2} : \frac{3}{2}

x = \frac{- ( - 5 ) - 1}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = 1

(x + \frac{1}{2}) (x - 2) = 0

4 x^{2} + 6 = 25 x

x^{2} + 8 x - 2 = 0

x^{2} + 7 x + 6 = 0

30 - 13 x - 15 x^{2} = 0

What are the solutions to the equation x(2x-5)=-3 ?
The solutions to the equation x(2x-5)=-3 are x= 3/2 ,x=1
Find the zeros of x(2x-5)=-3
The zeros of x(2x-5)=-3 are x= 3/2 ,x=1