What are the solutions to the equation -4x^2+14x-12=0 ?

The solutions to the equation -4x^2+14x-12=0 are x= 3/2 ,x=2

Find the zeros of -4x^2+14x-12=0

The zeros of -4x^2+14x-12=0 are x= 3/2 ,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 4 x^{2} + 14 x - 12 = 0

x = \frac{3}{2}, x = 2

Decimal Notation

x = 1.5, x = 2

Solution steps

- 4 x^{2} + 14 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 ( - 4 ) ( - 12 )}{2 ( - 4 )}

1 4^{2} - 4 (- 4) (- 12) = 2

x_{1, 2} = \frac{- 14 \pm 2}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 14 + 2}{2 ( - 4 )}, x_{2} = \frac{- 14 - 2}{2 ( - 4 )}

x = \frac{- 14 + 2}{2 ( - 4 )} : \frac{3}{2}

x = \frac{- 14 - 2}{2 ( - 4 )} : 2

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = 2

πa = \frac{1}{2} π r^{2}

x^{2} + 3 x = 10

2 (x - 5)^{2} - 64 = 0

s, A = s^{2}

x^{2} + 6 x + 2 = 0

What are the solutions to the equation -4x^2+14x-12=0 ?
The solutions to the equation -4x^2+14x-12=0 are x= 3/2 ,x=2
Find the zeros of -4x^2+14x-12=0
The zeros of -4x^2+14x-12=0 are x= 3/2 ,x=2