What are the solutions to the equation 9x^2+6x=-10 ?

The solutions to the equation 9x^2+6x=-10 are x=-1/3+i,x=-1/3-i

Find the zeros of 9x^2+6x=-10

The zeros of 9x^2+6x=-10 are x=-1/3+i,x=-1/3-i

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9 x^{2} + 6 x = - 10

x = - \frac{1}{3} + i, x = - \frac{1}{3} - i

Solution steps

9 x^{2} + 6 x = - 10

Move

10

to the left side

9 x^{2} + 6 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 10}{2 \cdot 9}

Simplify

6^{2} - 4 \cdot 9 \cdot 10 : 18 i

x_{1, 2} = \frac{- 6 \pm 18 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 6 + 18 i}{2 \cdot 9}, x_{2} = \frac{- 6 - 18 i}{2 \cdot 9}

x = \frac{- 6 + 18 i}{2 \cdot 9} : - \frac{1}{3} + i

x = \frac{- 6 - 18 i}{2 \cdot 9} : - \frac{1}{3} - i

The solutions to the quadratic equation are:

x = - \frac{1}{3} + i, x = - \frac{1}{3} - i

(x - 1) (3 x + 2) = 0

(11 x - 12)^{2} = 20

8 - (x + 4)^{2} = 4 - (0.5 x + 1.8)^{2}

(2 x) x - 1 = 4

9 x^{2} + 18 x + 14 = 0

What are the solutions to the equation 9x^2+6x=-10 ?
The solutions to the equation 9x^2+6x=-10 are x=-1/3+i,x=-1/3-i
Find the zeros of 9x^2+6x=-10
The zeros of 9x^2+6x=-10 are x=-1/3+i,x=-1/3-i