What are the solutions to the equation 9x^2+42x+53=0 ?

The solutions to the equation 9x^2+42x+53=0 are x=-7/3+i 2/3 ,x=-7/3-i 2/3

Find the zeros of 9x^2+42x+53=0

The zeros of 9x^2+42x+53=0 are x=-7/3+i 2/3 ,x=-7/3-i 2/3

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9 x^{2} + 42 x + 53 = 0

x = - \frac{7}{3} + i \frac{2}{3}, x = - \frac{7}{3} - i \frac{2}{3}

Solution steps

9 x^{2} + 42 x + 53 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 42 \pm 4 2 ^{2} - 4 \cdot 9 \cdot 53}{2 \cdot 9}

Simplify

4 2^{2} - 4 \cdot 9 \cdot 53 : 12 i

x_{1, 2} = \frac{- 42 \pm 12 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 42 + 12 i}{2 \cdot 9}, x_{2} = \frac{- 42 - 12 i}{2 \cdot 9}

x = \frac{- 42 + 12 i}{2 \cdot 9} : - \frac{7}{3} + i \frac{2}{3}

x = \frac{- 42 - 12 i}{2 \cdot 9} : - \frac{7}{3} - i \frac{2}{3}

The solutions to the quadratic equation are:

x = - \frac{7}{3} + i \frac{2}{3}, x = - \frac{7}{3} - i \frac{2}{3}

(x + 5) (x + 9) = 0

(x + 3) (x - 2) = 6

- 5 x^{2} - 90 x - 765 = 0

2 x - 3 x^{2} = 5

3 v^{2} + 18 v = 0

What are the solutions to the equation 9x^2+42x+53=0 ?
The solutions to the equation 9x^2+42x+53=0 are x=-7/3+i 2/3 ,x=-7/3-i 2/3
Find the zeros of 9x^2+42x+53=0
The zeros of 9x^2+42x+53=0 are x=-7/3+i 2/3 ,x=-7/3-i 2/3