What are the solutions to the equation 16t^2-80t+64=0 ?

The solutions to the equation 16t^2-80t+64=0 are t=4,t=1

Find the zeros of 16t^2-80t+64=0

The zeros of 16t^2-80t+64=0 are t=4,t=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16 t^{2} - 80 t + 64 = 0

t = 4, t = 1

Solution steps

16 t^{2} - 80 t + 64 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 80 ) \pm ( - 80 ) ^{2} - 4 \cdot 16 \cdot 64}{2 \cdot 16}

(- 80)^{2} - 4 \cdot 16 \cdot 64 = 48

t_{1, 2} = \frac{- ( - 80 ) \pm 48}{2 \cdot 16}

Separate the solutions

t_{1} = \frac{- ( - 80 ) + 48}{2 \cdot 16}, t_{2} = \frac{- ( - 80 ) - 48}{2 \cdot 16}

t = \frac{- ( - 80 ) + 48}{2 \cdot 16} : 4

t = \frac{- ( - 80 ) - 48}{2 \cdot 16} : 1

The solutions to the quadratic equation are:

t = 4, t = 1

3000 - 70 w = 100 w - w^{2}

(s^{2} + 8 s + 272) = 0

(x - 4)^{2} = - 36

11 x^{2} + 16 x - 21 = 0

- 4 x^{2} = 12 x

What are the solutions to the equation 16t^2-80t+64=0 ?
The solutions to the equation 16t^2-80t+64=0 are t=4,t=1
Find the zeros of 16t^2-80t+64=0
The zeros of 16t^2-80t+64=0 are t=4,t=1