What are the solutions to the equation -5x^2+101x-193=0 ?

The solutions to the equation -5x^2+101x-193=0 are x=(101-sqrt(6341))/(10),x=(101+sqrt(6341))/(10)

Find the zeros of -5x^2+101x-193=0

The zeros of -5x^2+101x-193=0 are x=(101-sqrt(6341))/(10),x=(101+sqrt(6341))/(10)

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- 5 x^{2} + 101 x - 193 = 0

x = \frac{101 - 6341}{10}, x = \frac{101 + 6341}{10}

Decimal Notation

x = 2.13696 \dots, x = 18.06303 \dots

Solution steps

- 5 x^{2} + 101 x - 193 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 101 \pm 10 1 ^{2} - 4 ( - 5 ) ( - 193 )}{2 ( - 5 )}

10 1^{2} - 4 (- 5) (- 193) = 6341

x_{1, 2} = \frac{- 101 \pm 6341}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 101 + 6341}{2 ( - 5 )}, x_{2} = \frac{- 101 - 6341}{2 ( - 5 )}

x = \frac{- 101 + 6341}{2 ( - 5 )} : \frac{101 - 6341}{10}

x = \frac{- 101 - 6341}{2 ( - 5 )} : \frac{101 + 6341}{10}

The solutions to the quadratic equation are:

x = \frac{101 - 6341}{10}, x = \frac{101 + 6341}{10}

x^{2} - 18 x - 3 = 0

- 4 = (x - 3)^{2} - 4

2 x^{2} - 6 = - 206

(x + 1) (x - 2) = 3 (x - 2)

2 x^{2} - x - 20 = 0

What are the solutions to the equation -5x^2+101x-193=0 ?
The solutions to the equation -5x^2+101x-193=0 are x=(101-sqrt(6341))/(10),x=(101+sqrt(6341))/(10)
Find the zeros of -5x^2+101x-193=0
The zeros of -5x^2+101x-193=0 are x=(101-sqrt(6341))/(10),x=(101+sqrt(6341))/(10)