What are the solutions to the equation -5x^2-2x+1=0 ?

The solutions to the equation -5x^2-2x+1=0 are x=-(1+sqrt(6))/5 ,x=(sqrt(6)-1)/5

Find the zeros of -5x^2-2x+1=0

The zeros of -5x^2-2x+1=0 are x=-(1+sqrt(6))/5 ,x=(sqrt(6)-1)/5

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- 5 x^{2} - 2 x + 1 = 0

x = - \frac{1 + 6}{5}, x = \frac{6 - 1}{5}

Decimal Notation

x = - 0.68989 \dots, x = 0.28989 \dots

Solution steps

- 5 x^{2} - 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 5 ) \cdot 1}{2 ( - 5 )}

(- 2)^{2} - 4 (- 5) \cdot 1 = 26

x_{1, 2} = \frac{- ( - 2 ) \pm 2 6}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 6}{2 ( - 5 )}, x_{2} = \frac{- ( - 2 ) - 2 6}{2 ( - 5 )}

x = \frac{- ( - 2 ) + 2 6}{2 ( - 5 )} : - \frac{1 + 6}{5}

x = \frac{- ( - 2 ) - 2 6}{2 ( - 5 )} : \frac{6 - 1}{5}

The solutions to the quadratic equation are:

x = - \frac{1 + 6}{5}, x = \frac{6 - 1}{5}

4 x^{2} + 16 x + 8 = 0

2 x (x + 3) = 1

2 x (x + 3) = 3

2 x (x + 3) = 2

(- x - 2) = x^{2} + 4

What are the solutions to the equation -5x^2-2x+1=0 ?
The solutions to the equation -5x^2-2x+1=0 are x=-(1+sqrt(6))/5 ,x=(sqrt(6)-1)/5
Find the zeros of -5x^2-2x+1=0
The zeros of -5x^2-2x+1=0 are x=-(1+sqrt(6))/5 ,x=(sqrt(6)-1)/5