What are the solutions to the equation (3+x^2)/7 =4 ?

The solutions to the equation (3+x^2)/7 =4 are x=5,x=-5

Find the zeros of (3+x^2)/7 =4

The zeros of (3+x^2)/7 =4 are x=5,x=-5

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\frac{3 + x ^{2}}{7} = 4

x = 5, x = - 5

Solution steps

\frac{3 + x ^{2}}{7} = 4

Multiply both sides by

7

3 + x^{2} = 28

Move

3

to the right side

x^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 25, x = - 25

25 = 5

- 25 = - 5

x = 5, x = - 5

5 x^{2} = 2 x + 1

x, n x^{2} - k x + 64 = 0

t (t) = 25 - 2 t, 0 \leq t \leq 10

1 0^{2} + 8^{2} = c^{2}

- x^{2} - 4 x + 1

What are the solutions to the equation (3+x^2)/7 =4 ?
The solutions to the equation (3+x^2)/7 =4 are x=5,x=-5
Find the zeros of (3+x^2)/7 =4
The zeros of (3+x^2)/7 =4 are x=5,x=-5