What are the solutions to the equation 10^2+8^2=c^2 ?

The solutions to the equation 10^2+8^2=c^2 are c=2sqrt(41),c=-2sqrt(41)

Find the zeros of 10^2+8^2=c^2

The zeros of 10^2+8^2=c^2 are c=2sqrt(41),c=-2sqrt(41)

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1 0^{2} + 8^{2} = c^{2}

c = 241, c = - 241

Decimal Notation

c = 12.80624 \dots, c = - 12.80624 \dots

Solution steps

1 0^{2} + 8^{2} = c^{2}

Switch sides

c^{2} = 1 0^{2} + 8^{2}

Simplify

1 0^{2} + 8^{2} : 164

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 164, c = - 164

164 = 241

- 164 = - 241

c = 241, c = - 241

- x^{2} - 4 x + 1

4 x (2 - x) = 0

(5 x + 2) (x - 1) = 7 x

t^{2} + 3 t + 2 = 0

(x - 1)^{2} = 14

What are the solutions to the equation 10^2+8^2=c^2 ?
The solutions to the equation 10^2+8^2=c^2 are c=2sqrt(41),c=-2sqrt(41)
Find the zeros of 10^2+8^2=c^2
The zeros of 10^2+8^2=c^2 are c=2sqrt(41),c=-2sqrt(41)