What are the solutions to the equation ax^2+(a+b)x+b=0 ?

The solutions to the equation ax^2+(a+b)x+b=0 are x=-b/a ,x=-1;\quad a\ne 0

Find the zeros of ax^2+(a+b)x+b=0

The zeros of ax^2+(a+b)x+b=0 are x=-b/a ,x=-1;\quad a\ne 0

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a x^{2} + (a + b) x + b = 0

x = - \frac{b}{a}, x = - 1; a \neq = 0

Solution steps

a x^{2} + (a + b) x + b = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( a + b ) \pm ( a + b ) ^{2} - 4 ab}{2 a}

Simplify

(a + b)^{2} - 4 ab : a - b

x_{1, 2} = \frac{- ( a + b ) \pm ( a - b )}{2 a}; a \neq = 0

Separate the solutions

x_{1} = \frac{- ( a + b ) + a - b}{2 a}, x_{2} = \frac{- ( a + b ) - ( a - b )}{2 a}

x = \frac{- ( a + b ) + a - b}{2 a} : - \frac{b}{a}

x = \frac{- ( a + b ) - ( a - b )}{2 a} : - 1

The solutions to the quadratic equation are:

x = - \frac{b}{a}, x = - 1; a \neq = 0

x + 3 = 39 - x^{2}

y = y (4 - y)

x^{2} - 10 x = - 22

a = (x - 6) (x - 20) - (x - 3) 2 + 50

(π t - 4)^{2} = 4.1 t - 3

What are the solutions to the equation ax^2+(a+b)x+b=0 ?
The solutions to the equation ax^2+(a+b)x+b=0 are x=-b/a ,x=-1;\quad a\ne 0
Find the zeros of ax^2+(a+b)x+b=0
The zeros of ax^2+(a+b)x+b=0 are x=-b/a ,x=-1;\quad a\ne 0