What are the solutions to the equation x^2-10x=-22 ?

The solutions to the equation x^2-10x=-22 are x=5+sqrt(3),x=5-sqrt(3)

Find the zeros of x^2-10x=-22

The zeros of x^2-10x=-22 are x=5+sqrt(3),x=5-sqrt(3)

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x^{2} - 10 x = - 22

x = 5 + 3, x = 5 - 3

Decimal Notation

x = 6.73205 \dots, x = 3.26794 \dots

Solution steps

x^{2} - 10 x = - 22

Move

22

to the left side

x^{2} - 10 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 22}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 22 = 23

x_{1, 2} = \frac{- ( - 10 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 3}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 3}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 3}{2 \cdot 1} : 5 + 3

x = \frac{- ( - 10 ) - 2 3}{2 \cdot 1} : 5 - 3

The solutions to the quadratic equation are:

x = 5 + 3, x = 5 - 3

a = (x - 6) (x - 20) - (x - 3) 2 + 50

(π t - 4)^{2} = 4.1 t - 3

- 6 x = - 9 x^{2} + 8

k^{2} + 10 k + 16 = 0

18 x^{2} - 7 x = 1

What are the solutions to the equation x^2-10x=-22 ?
The solutions to the equation x^2-10x=-22 are x=5+sqrt(3),x=5-sqrt(3)
Find the zeros of x^2-10x=-22
The zeros of x^2-10x=-22 are x=5+sqrt(3),x=5-sqrt(3)