What are the solutions to the equation -49x^2=56 ?

The solutions to the equation -49x^2=56 are x=(2sqrt(2))/(sqrt(7))i,x=-(2sqrt(2))/(sqrt(7))i

Find the zeros of -49x^2=56

The zeros of -49x^2=56 are x=(2sqrt(2))/(sqrt(7))i,x=-(2sqrt(2))/(sqrt(7))i

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- 49 x^{2} = 56

x = \frac{2 2}{7} i, x = - \frac{2 2}{7} i

Solution steps

- 49 x^{2} = 56

Divide both sides by

- 49

x^{2} = - \frac{8}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{8}{7}, x = - - \frac{8}{7}

- \frac{8}{7} = \frac{2 2}{7} i

- - \frac{8}{7} = - \frac{2 2}{7} i

x = \frac{2 2}{7} i, x = - \frac{2 2}{7} i

x^{2} + 6 x - 12 = 0

(x - \frac{3}{2})^{2} = 0

x^{2} - 4 x + 8 = 13

4 a^{2} + 432 = 0

m (x) = 3 x^{2} + x - 5 m (\frac{1}{2})

What are the solutions to the equation -49x^2=56 ?
The solutions to the equation -49x^2=56 are x=(2sqrt(2))/(sqrt(7))i,x=-(2sqrt(2))/(sqrt(7))i
Find the zeros of -49x^2=56
The zeros of -49x^2=56 are x=(2sqrt(2))/(sqrt(7))i,x=-(2sqrt(2))/(sqrt(7))i