What are the solutions to the equation 3x^2-2x+12=0 ?

The solutions to the equation 3x^2-2x+12=0 are x= 1/3+i(sqrt(35))/3 ,x= 1/3-i(sqrt(35))/3

Find the zeros of 3x^2-2x+12=0

The zeros of 3x^2-2x+12=0 are x= 1/3+i(sqrt(35))/3 ,x= 1/3-i(sqrt(35))/3

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3 x^{2} - 2 x + 12 = 0

x = \frac{1}{3} + i \frac{35}{3}, x = \frac{1}{3} - i \frac{35}{3}

Solution steps

3 x^{2} - 2 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

Simplify

(- 2)^{2} - 4 \cdot 3 \cdot 12 : 235 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 35 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 35 i}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 35 i}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 35 i}{2 \cdot 3} : \frac{1}{3} + i \frac{35}{3}

x = \frac{- ( - 2 ) - 2 35 i}{2 \cdot 3} : \frac{1}{3} - i \frac{35}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} + i \frac{35}{3}, x = \frac{1}{3} - i \frac{35}{3}

9 x + 9 x^{2} - 4 = 0

(3 x + 5)^{2} = 0

6 x^{2} + 3 = - 11 x

5 y (2 y - 5) = 0

x^{1} + 2 x^{2} = 8, 3 x^{1} - 4 x^{2} = 4

What are the solutions to the equation 3x^2-2x+12=0 ?
The solutions to the equation 3x^2-2x+12=0 are x= 1/3+i(sqrt(35))/3 ,x= 1/3-i(sqrt(35))/3
Find the zeros of 3x^2-2x+12=0
The zeros of 3x^2-2x+12=0 are x= 1/3+i(sqrt(35))/3 ,x= 1/3-i(sqrt(35))/3