What are the solutions to the equation 5y(2y-5)=0 ?

The solutions to the equation 5y(2y-5)=0 are y=0,y= 5/2

Find the zeros of 5y(2y-5)=0

The zeros of 5y(2y-5)=0 are y=0,y= 5/2

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5 y (2 y - 5) = 0

y = 0, y = \frac{5}{2}

Decimal Notation

y = 0, y = 2.5

Solution steps

5 y (2 y - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 2 y - 5 = 0

Solve

2 y - 5 = 0 : y = \frac{5}{2}

The solutions to the quadratic equation are:

y = 0, y = \frac{5}{2}

x^{1} + 2 x^{2} = 8, 3 x^{1} - 4 x^{2} = 4

10 t^{2} - 4 t - 32 = 0

- 5 x^{2} + 3 = 2

7 p^{2} + 10 = 26

9 v^{2} + 4 = 571

What are the solutions to the equation 5y(2y-5)=0 ?
The solutions to the equation 5y(2y-5)=0 are y=0,y= 5/2
Find the zeros of 5y(2y-5)=0
The zeros of 5y(2y-5)=0 are y=0,y= 5/2