What are the solutions to the equation solvefor x,2x^2-5x-1=0 ?

The solutions to the equation solvefor x,2x^2-5x-1=0 are x=(5+sqrt(33))/4 ,x=(5-sqrt(33))/4

Find the zeros of solvefor x,2x^2-5x-1=0

The zeros of solvefor x,2x^2-5x-1=0 are x=(5+sqrt(33))/4 ,x=(5-sqrt(33))/4

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x, 2 x^{2} - 5 x - 1 = 0

x = \frac{5 + 33}{4}, x = \frac{5 - 33}{4}

Decimal Notation

x = 2.68614 \dots, x = - 0.18614 \dots

Solution steps

2 x^{2} - 5 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 1) = 33

x_{1, 2} = \frac{- ( - 5 ) \pm 33}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 33}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 33}{2 \cdot 2}

x = \frac{- ( - 5 ) + 33}{2 \cdot 2} : \frac{5 + 33}{4}

x = \frac{- ( - 5 ) - 33}{2 \cdot 2} : \frac{5 - 33}{4}

The solutions to the quadratic equation are:

x = \frac{5 + 33}{4}, x = \frac{5 - 33}{4}

3 x^{2} - 15 x - x + 5 = 0

8 x^{2} + 2 x + 2 = 0

x, z = 2 x^{2} y^{3}

x^{2} - 3 = 8 x - 10

m^{2} = 3 (m - 1)

What are the solutions to the equation solvefor x,2x^2-5x-1=0 ?
The solutions to the equation solvefor x,2x^2-5x-1=0 are x=(5+sqrt(33))/4 ,x=(5-sqrt(33))/4
Find the zeros of solvefor x,2x^2-5x-1=0
The zeros of solvefor x,2x^2-5x-1=0 are x=(5+sqrt(33))/4 ,x=(5-sqrt(33))/4