What are the solutions to the equation x^2-3=8x-10 ?

The solutions to the equation x^2-3=8x-10 are x=7,x=1

Find the zeros of x^2-3=8x-10

The zeros of x^2-3=8x-10 are x=7,x=1

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x^{2} - 3 = 8 x - 10

x = 7, x = 1

Solution steps

x^{2} - 3 = 8 x - 10

Move

10

to the left side

x^{2} + 7 = 8 x

Move

8 x

to the left side

x^{2} + 7 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 8 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 7 = 6

x_{1, 2} = \frac{- ( - 8 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 6}{2 \cdot 1}

x = \frac{- ( - 8 ) + 6}{2 \cdot 1} : 7

x = \frac{- ( - 8 ) - 6}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 7, x = 1

m^{2} = 3 (m - 1)

4 x^{2} + 8 x + 3 = 0

5 x^{2} - 18 = 0

4 x^{2} - 20 x + 100 = 0

8 x^{2} - 6 x - 2 = 0

What are the solutions to the equation x^2-3=8x-10 ?
The solutions to the equation x^2-3=8x-10 are x=7,x=1
Find the zeros of x^2-3=8x-10
The zeros of x^2-3=8x-10 are x=7,x=1