What are the solutions to the equation 4.9t^2+8t-30=0 ?

The solutions to the equation 4.9t^2+8t-30=0 are t=(10(sqrt(163)-4))/(49),t=-(10(4+sqrt(163)))/(49)

Find the zeros of 4.9t^2+8t-30=0

The zeros of 4.9t^2+8t-30=0 are t=(10(sqrt(163)-4))/(49),t=-(10(4+sqrt(163)))/(49)

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4.9 t^{2} + 8 t - 30 = 0

t = \frac{10 ( 163 - 4 )}{49}, t = - \frac{10 ( 4 + 163 )}{49}

Decimal Notation

t = 1.78921 \dots, t = - 3.42186 \dots

Solution steps

4.9 t^{2} + 8 t - 30 = 0

Multiply both sides by

10

49 t^{2} + 80 t - 300 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 \cdot 49 ( - 300 )}{2 \cdot 49}

8 0^{2} - 4 \cdot 49 (- 300) = 20163

t_{1, 2} = \frac{- 80 \pm 20 163}{2 \cdot 49}

Separate the solutions

t_{1} = \frac{- 80 + 20 163}{2 \cdot 49}, t_{2} = \frac{- 80 - 20 163}{2 \cdot 49}

t = \frac{- 80 + 20 163}{2 \cdot 49} : \frac{10 ( 163 - 4 )}{49}

t = \frac{- 80 - 20 163}{2 \cdot 49} : - \frac{10 ( 4 + 163 )}{49}

The solutions to the quadratic equation are:

t = \frac{10 ( 163 - 4 )}{49}, t = - \frac{10 ( 4 + 163 )}{49}

6 - 2 x^{2} = 1

v^{2} + 3 v - 10 = 0

2 p^{2} - 3 p + 1 = 0

x^{2} - 2 x + 3 = \frac{x}{2} + 2

5 x = x^{2} + 6

What are the solutions to the equation 4.9t^2+8t-30=0 ?
The solutions to the equation 4.9t^2+8t-30=0 are t=(10(sqrt(163)-4))/(49),t=-(10(4+sqrt(163)))/(49)
Find the zeros of 4.9t^2+8t-30=0
The zeros of 4.9t^2+8t-30=0 are t=(10(sqrt(163)-4))/(49),t=-(10(4+sqrt(163)))/(49)