What are the solutions to the equation solvefor x,2xy=x^2+y^2 ?

The solutions to the equation solvefor x,2xy=x^2+y^2 are x=y

Find the zeros of solvefor x,2xy=x^2+y^2

The zeros of solvefor x,2xy=x^2+y^2 are x=y

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solve for

x, 2 x y = x^{2} + y^{2}

x = y

Solution steps

2 x y = x^{2} + y^{2}

Switch sides

x^{2} + y^{2} = 2 x y

Move

2 x y

to the left side

x^{2} + y^{2} - 2 x y = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 y x + y^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 y ) \pm ( - 2 y ) ^{2} - 4 \cdot 1 \cdot y ^{2}}{2 \cdot 1}

(- 2 y)^{2} - 4 \cdot 1 \cdot y^{2} = 0

x_{1, 2} = \frac{- ( - 2 y ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 2 y )}{2 \cdot 1}

Simplify

\frac{- ( - 2 y )}{2 \cdot 1} : y

x = y

The solution to the quadratic equation is:

x = y

3 x (4 - x) = 15

1890 = \frac{1}{10} x (300 - x)

x^{2} - 14 x - 31 = 0

3 x (x - 2) - x^{2} = (x - 3) (x + 5)

x^{2} + 5 x + 5

What are the solutions to the equation solvefor x,2xy=x^2+y^2 ?
The solutions to the equation solvefor x,2xy=x^2+y^2 are x=y
Find the zeros of solvefor x,2xy=x^2+y^2
The zeros of solvefor x,2xy=x^2+y^2 are x=y