What are the solutions to the equation x^2-14x-31=0 ?

The solutions to the equation x^2-14x-31=0 are x=7+4sqrt(5),x=7-4sqrt(5)

Find the zeros of x^2-14x-31=0

The zeros of x^2-14x-31=0 are x=7+4sqrt(5),x=7-4sqrt(5)

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x^{2} - 14 x - 31 = 0

x = 7 + 45, x = 7 - 45

Decimal Notation

x = 15.94427 \dots, x = - 1.94427 \dots

Solution steps

x^{2} - 14 x - 31 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot ( - 31 )}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot (- 31) = 85

x_{1, 2} = \frac{- ( - 14 ) \pm 8 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 8 5}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 8 5}{2 \cdot 1}

x = \frac{- ( - 14 ) + 8 5}{2 \cdot 1} : 7 + 45

x = \frac{- ( - 14 ) - 8 5}{2 \cdot 1} : 7 - 45

The solutions to the quadratic equation are:

x = 7 + 45, x = 7 - 45

3 x (x - 2) - x^{2} = (x - 3) (x + 5)

x^{2} + 5 x + 5

x^{2} + 5 x + 9

6 m^{2} + 3 m + 2 = 0

20 = - 2.7 t^{2} + 40 t + 6.5

What are the solutions to the equation x^2-14x-31=0 ?
The solutions to the equation x^2-14x-31=0 are x=7+4sqrt(5),x=7-4sqrt(5)
Find the zeros of x^2-14x-31=0
The zeros of x^2-14x-31=0 are x=7+4sqrt(5),x=7-4sqrt(5)