What are the solutions to the equation 6m^2+3m+2=0 ?

The solutions to the equation 6m^2+3m+2=0 are m=-1/4+i(sqrt(39))/(12),m=-1/4-i(sqrt(39))/(12)

Find the zeros of 6m^2+3m+2=0

The zeros of 6m^2+3m+2=0 are m=-1/4+i(sqrt(39))/(12),m=-1/4-i(sqrt(39))/(12)

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6 m^{2} + 3 m + 2 = 0

m = - \frac{1}{4} + i \frac{39}{12}, m = - \frac{1}{4} - i \frac{39}{12}

Solution steps

6 m^{2} + 3 m + 2 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 6 \cdot 2}{2 \cdot 6}

Simplify

3^{2} - 4 \cdot 6 \cdot 2 : 39 i

m_{1, 2} = \frac{- 3 \pm 39 i}{2 \cdot 6}

Separate the solutions

m_{1} = \frac{- 3 + 39 i}{2 \cdot 6}, m_{2} = \frac{- 3 - 39 i}{2 \cdot 6}

m = \frac{- 3 + 39 i}{2 \cdot 6} : - \frac{1}{4} + i \frac{39}{12}

m = \frac{- 3 - 39 i}{2 \cdot 6} : - \frac{1}{4} - i \frac{39}{12}

The solutions to the quadratic equation are:

m = - \frac{1}{4} + i \frac{39}{12}, m = - \frac{1}{4} - i \frac{39}{12}

20 = - 2.7 t^{2} + 40 t + 6.5

2 (x + 2) (x - 2) = 0

x (6 + x) = 1

(p - 2) (p - 5) = 3

(x + 2)^{2} = 17

What are the solutions to the equation 6m^2+3m+2=0 ?
The solutions to the equation 6m^2+3m+2=0 are m=-1/4+i(sqrt(39))/(12),m=-1/4-i(sqrt(39))/(12)
Find the zeros of 6m^2+3m+2=0
The zeros of 6m^2+3m+2=0 are m=-1/4+i(sqrt(39))/(12),m=-1/4-i(sqrt(39))/(12)