What are the solutions to the equation u^2+4u+3=0 ?

The solutions to the equation u^2+4u+3=0 are u=-1,u=-3

Find the zeros of u^2+4u+3=0

The zeros of u^2+4u+3=0 are u=-1,u=-3

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u^{2} + 4 u + 3 = 0

u = - 1, u = - 3

Solution steps

u^{2} + 4 u + 3 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 3 = 2

u_{1, 2} = \frac{- 4 \pm 2}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 4 + 2}{2 \cdot 1}, u_{2} = \frac{- 4 - 2}{2 \cdot 1}

u = \frac{- 4 + 2}{2 \cdot 1} : - 1

u = \frac{- 4 - 2}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

u = - 1, u = - 3

- 3 x + x^{2} - 4 = - 8 + x

6 x (x - 1) = 63 - 19 x

6 x^{2} - x - 15 = 0

(x - 9) (x + 7) = 1

4 (x^{2} - x) = x^{2} - 3

What are the solutions to the equation u^2+4u+3=0 ?
The solutions to the equation u^2+4u+3=0 are u=-1,u=-3
Find the zeros of u^2+4u+3=0
The zeros of u^2+4u+3=0 are u=-1,u=-3