What are the solutions to the equation (x-9)(x+7)=1 ?

The solutions to the equation (x-9)(x+7)=1 are x=1+sqrt(65),x=1-sqrt(65)

Find the zeros of (x-9)(x+7)=1

The zeros of (x-9)(x+7)=1 are x=1+sqrt(65),x=1-sqrt(65)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 9) (x + 7) = 1

x = 1 + 65, x = 1 - 65

Decimal Notation

x = 9.06225 \dots, x = - 7.06225 \dots

Solution steps

(x - 9) (x + 7) = 1

Expand

(x - 9) (x + 7) : x^{2} - 2 x - 63

x^{2} - 2 x - 63 = 1

Move

1

to the left side

x^{2} - 2 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 64 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 64) = 265

x_{1, 2} = \frac{- ( - 2 ) \pm 2 65}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 65}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 65}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 65}{2 \cdot 1} : 1 + 65

x = \frac{- ( - 2 ) - 2 65}{2 \cdot 1} : 1 - 65

The solutions to the quadratic equation are:

x = 1 + 65, x = 1 - 65

4 (x^{2} - x) = x^{2} - 3

4 (x^{2} - x) = x^{2} - 2

- 6 = 5 x + x^{2}

25 x^{2} - 241 x + 144 = 0

7 x^{2} + 11 x - 1 = 0

What are the solutions to the equation (x-9)(x+7)=1 ?
The solutions to the equation (x-9)(x+7)=1 are x=1+sqrt(65),x=1-sqrt(65)
Find the zeros of (x-9)(x+7)=1
The zeros of (x-9)(x+7)=1 are x=1+sqrt(65),x=1-sqrt(65)