What are the solutions to the equation 7x^2+11x-1=0 ?

The solutions to the equation 7x^2+11x-1=0 are x=(-11+sqrt(149))/(14),x=(-11-sqrt(149))/(14)

Find the zeros of 7x^2+11x-1=0

The zeros of 7x^2+11x-1=0 are x=(-11+sqrt(149))/(14),x=(-11-sqrt(149))/(14)

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7 x^{2} + 11 x - 1 = 0

x = \frac{- 11 + 149}{14}, x = \frac{- 11 - 149}{14}

Decimal Notation

x = 0.08618 \dots, x = - 1.65761 \dots

Solution steps

7 x^{2} + 11 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 7 ( - 1 )}{2 \cdot 7}

1 1^{2} - 4 \cdot 7 (- 1) = 149

x_{1, 2} = \frac{- 11 \pm 149}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 11 + 149}{2 \cdot 7}, x_{2} = \frac{- 11 - 149}{2 \cdot 7}

x = \frac{- 11 + 149}{2 \cdot 7} : \frac{- 11 + 149}{14}

x = \frac{- 11 - 149}{2 \cdot 7} : \frac{- 11 - 149}{14}

The solutions to the quadratic equation are:

x = \frac{- 11 + 149}{14}, x = \frac{- 11 - 149}{14}

4 x^{2} + 1 = 4 x

32 = x^{2} - 3 x + 4

9 x^{2} - 2 = 3 x

4 x^{2} + 8 x = 7

x, x^{2} y - 9 y - 3 x^{2} = 0

What are the solutions to the equation 7x^2+11x-1=0 ?
The solutions to the equation 7x^2+11x-1=0 are x=(-11+sqrt(149))/(14),x=(-11-sqrt(149))/(14)
Find the zeros of 7x^2+11x-1=0
The zeros of 7x^2+11x-1=0 are x=(-11+sqrt(149))/(14),x=(-11-sqrt(149))/(14)