What are the solutions to the equation factor 4x^2+1=4x ?

The solutions to the equation factor 4x^2+1=4x are x= 1/2

Find the zeros of factor 4x^2+1=4x

The zeros of factor 4x^2+1=4x are x= 1/2

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4 x^{2} + 1 = 4 x

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

4 x^{2} + 1 = 4 x

Move

4 x

to the left side

4 x^{2} + 1 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 4 x + 1 = 0

Factor

4 x^{2} - 4 x + 1 : (2 x - 1)^{2}

(2 x - 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

32 = x^{2} - 3 x + 4

9 x^{2} - 2 = 3 x

4 x^{2} + 8 x = 7

x, x^{2} y - 9 y - 3 x^{2} = 0

4 x^{2} - x = 0

What are the solutions to the equation factor 4x^2+1=4x ?
The solutions to the equation factor 4x^2+1=4x are x= 1/2
Find the zeros of factor 4x^2+1=4x
The zeros of factor 4x^2+1=4x are x= 1/2