What are the solutions to the equation y^2+4y-3=0 ?

The solutions to the equation y^2+4y-3=0 are y=-2+sqrt(7),y=-2-sqrt(7)

Find the zeros of y^2+4y-3=0

The zeros of y^2+4y-3=0 are y=-2+sqrt(7),y=-2-sqrt(7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} + 4 y - 3 = 0

y = - 2 + 7, y = - 2 - 7

Decimal Notation

y = 0.64575 \dots, y = - 4.64575 \dots

Solution steps

y^{2} + 4 y - 3 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 3) = 27

y_{1, 2} = \frac{- 4 \pm 2 7}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 4 + 2 7}{2 \cdot 1}, y_{2} = \frac{- 4 - 2 7}{2 \cdot 1}

y = \frac{- 4 + 2 7}{2 \cdot 1} : - 2 + 7

y = \frac{- 4 - 2 7}{2 \cdot 1} : - 2 - 7

The solutions to the quadratic equation are:

y = - 2 + 7, y = - 2 - 7

3 x^{2} + 5 x + \frac{3}{4} = 0

0 = 2 (x - 3)^{2} + 5

14 x^{2} + 7 x = 0

t^{2} - 8 t + 1 = 0

k^{2} - 4 k - 5 = 0

What are the solutions to the equation y^2+4y-3=0 ?
The solutions to the equation y^2+4y-3=0 are y=-2+sqrt(7),y=-2-sqrt(7)
Find the zeros of y^2+4y-3=0
The zeros of y^2+4y-3=0 are y=-2+sqrt(7),y=-2-sqrt(7)