What are the solutions to the equation 16x^2+6x-1=0 ?

The solutions to the equation 16x^2+6x-1=0 are x= 1/8 ,x=-1/2

Find the zeros of 16x^2+6x-1=0

The zeros of 16x^2+6x-1=0 are x= 1/8 ,x=-1/2

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16 x^{2} + 6 x - 1 = 0

x = \frac{1}{8}, x = - \frac{1}{2}

Decimal Notation

x = 0.125, x = - 0.5

Solution steps

16 x^{2} + 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 16 ( - 1 )}{2 \cdot 16}

6^{2} - 4 \cdot 16 (- 1) = 10

x_{1, 2} = \frac{- 6 \pm 10}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- 6 + 10}{2 \cdot 16}, x_{2} = \frac{- 6 - 10}{2 \cdot 16}

x = \frac{- 6 + 10}{2 \cdot 16} : \frac{1}{8}

x = \frac{- 6 - 10}{2 \cdot 16} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{1}{8}, x = - \frac{1}{2}

7 x^{2} - 11 x - 12 = 0

2 x^{2} - 5 x - 21 = 0

x, x^{2} + 7 x - 2 = 0

x^{2} + 5 x - 6.25 = 43.75

x^{2} + 83 = - 20 x

What are the solutions to the equation 16x^2+6x-1=0 ?
The solutions to the equation 16x^2+6x-1=0 are x= 1/8 ,x=-1/2
Find the zeros of 16x^2+6x-1=0
The zeros of 16x^2+6x-1=0 are x= 1/8 ,x=-1/2