What are the solutions to the equation 5x^2+48x-20=0 ?

The solutions to the equation 5x^2+48x-20=0 are x= 2/5 ,x=-10

Find the zeros of 5x^2+48x-20=0

The zeros of 5x^2+48x-20=0 are x= 2/5 ,x=-10

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5 x^{2} + 48 x - 20 = 0

x = \frac{2}{5}, x = - 10

Decimal Notation

x = 0.4, x = - 10

Solution steps

5 x^{2} + 48 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 \cdot 5 ( - 20 )}{2 \cdot 5}

4 8^{2} - 4 \cdot 5 (- 20) = 52

x_{1, 2} = \frac{- 48 \pm 52}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 48 + 52}{2 \cdot 5}, x_{2} = \frac{- 48 - 52}{2 \cdot 5}

x = \frac{- 48 + 52}{2 \cdot 5} : \frac{2}{5}

x = \frac{- 48 - 52}{2 \cdot 5} : - 10

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = - 10

(3 x - 6)^{2} = 33

- 3 x^{2} + 8 = x + 2

6 x + 7.2 + (- 9.9) x^{2} = 0

9 x^{2} + 15 x = 14

z^{2} - 13 z = - 42

What are the solutions to the equation 5x^2+48x-20=0 ?
The solutions to the equation 5x^2+48x-20=0 are x= 2/5 ,x=-10
Find the zeros of 5x^2+48x-20=0
The zeros of 5x^2+48x-20=0 are x= 2/5 ,x=-10