What are the solutions to the equation (4x+3)^2=0 ?

The solutions to the equation (4x+3)^2=0 are x=-3/4

Find the zeros of (4x+3)^2=0

The zeros of (4x+3)^2=0 are x=-3/4

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(4 x + 3)^{2} = 0

x = - \frac{3}{4}

Decimal Notation

x = - 0.75

Solution steps

(4 x + 3)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

4 x + 3 = 0 : x = - \frac{3}{4}

The solution to the quadratic equation is:

x = - \frac{3}{4}

x^{2} + 6 x + 9 = - 3 x + 9

(2 - x)^{2} + (2 - x) - 20 = 0

2 x (x + 4) = (x + 3) (x - 3)

z^{2} - 5 \cdot 25 = 1 0^{2}

(2 x + 3) = x (1 - 3 x)

What are the solutions to the equation (4x+3)^2=0 ?
The solutions to the equation (4x+3)^2=0 are x=-3/4
Find the zeros of (4x+3)^2=0
The zeros of (4x+3)^2=0 are x=-3/4