What are the solutions to the equation 40(T^2+1)=41(T^2-1) ?

The solutions to the equation 40(T^2+1)=41(T^2-1) are T=9,T=-9

Find the zeros of 40(T^2+1)=41(T^2-1)

The zeros of 40(T^2+1)=41(T^2-1) are T=9,T=-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

40 (T^{2} + 1) = 41 (T^{2} - 1)

T = 9, T = - 9

Solution steps

40 (T^{2} + 1) = 41 (T^{2} - 1)

Expand

40 (T^{2} + 1) : 40 T^{2} + 40

Expand

41 (T^{2} - 1) : 41 T^{2} - 41

40 T^{2} + 40 = 41 T^{2} - 41

Move

40

to the right side

40 T^{2} = 41 T^{2} - 81

Move

41 T^{2}

to the left side

- T^{2} = - 81

Divide both sides by

- 1

T^{2} = 81

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

T = 81, T = - 81

81 = 9

- 81 = - 9

T = 9, T = - 9

125 = \frac{x ^{2}}{10}

6^{2} = 2 x^{2}

2 n^{2} - 5 n = - 290

5 x^{2} = 140 + 15 x

54 = 6 (2 x - 1)^{2}

What are the solutions to the equation 40(T^2+1)=41(T^2-1) ?
The solutions to the equation 40(T^2+1)=41(T^2-1) are T=9,T=-9
Find the zeros of 40(T^2+1)=41(T^2-1)
The zeros of 40(T^2+1)=41(T^2-1) are T=9,T=-9