What are the solutions to the equation 5x^2=140+15x ?

The solutions to the equation 5x^2=140+15x are x=7,x=-4

Find the zeros of 5x^2=140+15x

The zeros of 5x^2=140+15x are x=7,x=-4

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5 x^{2} = 140 + 15 x

x = 7, x = - 4

Solution steps

5 x^{2} = 140 + 15 x

Move

15 x

to the left side

5 x^{2} - 15 x = 140

Move

140

to the left side

5 x^{2} - 15 x - 140 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 5 ( - 140 )}{2 \cdot 5}

(- 15)^{2} - 4 \cdot 5 (- 140) = 55

x_{1, 2} = \frac{- ( - 15 ) \pm 55}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 55}{2 \cdot 5}, x_{2} = \frac{- ( - 15 ) - 55}{2 \cdot 5}

x = \frac{- ( - 15 ) + 55}{2 \cdot 5} : 7

x = \frac{- ( - 15 ) - 55}{2 \cdot 5} : - 4

The solutions to the quadratic equation are:

x = 7, x = - 4

54 = 6 (2 x - 1)^{2}

7 x^{2} - 28 x + 28 = 0

6 x^{2} + 5 = 17 x

5 x + 6 - x^{2} = x^{2} - 2 x - 3

10 x^{2} - 23 x - 5 = 0

What are the solutions to the equation 5x^2=140+15x ?
The solutions to the equation 5x^2=140+15x are x=7,x=-4
Find the zeros of 5x^2=140+15x
The zeros of 5x^2=140+15x are x=7,x=-4