What are the solutions to the equation 5x+6-x^2=x^2-2x-3 ?

The solutions to the equation 5x+6-x^2=x^2-2x-3 are x=-1,x= 9/2

Find the zeros of 5x+6-x^2=x^2-2x-3

The zeros of 5x+6-x^2=x^2-2x-3 are x=-1,x= 9/2

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5 x + 6 - x^{2} = x^{2} - 2 x - 3

x = - 1, x = \frac{9}{2}

Decimal Notation

x = - 1, x = 4.5

Solution steps

5 x + 6 - x^{2} = x^{2} - 2 x - 3

Move

3

to the left side

- x^{2} + 5 x + 9 = x^{2} - 2 x

Move

2 x

to the left side

- x^{2} + 7 x + 9 = x^{2}

Move

x^{2}

to the left side

- 2 x^{2} + 7 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 2 ) \cdot 9}{2 ( - 2 )}

7^{2} - 4 (- 2) \cdot 9 = 11

x_{1, 2} = \frac{- 7 \pm 11}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 7 + 11}{2 ( - 2 )}, x_{2} = \frac{- 7 - 11}{2 ( - 2 )}

x = \frac{- 7 + 11}{2 ( - 2 )} : - 1

x = \frac{- 7 - 11}{2 ( - 2 )} : \frac{9}{2}

The solutions to the quadratic equation are:

x = - 1, x = \frac{9}{2}

10 x^{2} - 23 x - 5 = 0

2 x^{2} - 3 = 1

- 3 (x + 3)^{2} - 10 = 20

z (z - 2) = - 5

(x + 3) (x + 3) = 1

What are the solutions to the equation 5x+6-x^2=x^2-2x-3 ?
The solutions to the equation 5x+6-x^2=x^2-2x-3 are x=-1,x= 9/2
Find the zeros of 5x+6-x^2=x^2-2x-3
The zeros of 5x+6-x^2=x^2-2x-3 are x=-1,x= 9/2