What are the solutions to the equation (x+3)(x+3)=1 ?

The solutions to the equation (x+3)(x+3)=1 are x=-2,x=-4

Find the zeros of (x+3)(x+3)=1

The zeros of (x+3)(x+3)=1 are x=-2,x=-4

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(x + 3) (x + 3) = 1

x = - 2, x = - 4

Solution steps

(x + 3) (x + 3) = 1

Simplify

(x + 3)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 1 : x = - 2

Solve

x + 3 = - 1 : x = - 4

The solutions to the quadratic equation are:

x = - 2, x = - 4

y^{2} + 12 y + 36 = 0

x^{2} + 5 x + 1.25 = 0

(x + 2)^{2} = 2 x + 2

3 a^{2} - 5 a - 2 = 0

x^{2} - 2 x + 5 = 48

What are the solutions to the equation (x+3)(x+3)=1 ?
The solutions to the equation (x+3)(x+3)=1 are x=-2,x=-4
Find the zeros of (x+3)(x+3)=1
The zeros of (x+3)(x+3)=1 are x=-2,x=-4