What are the solutions to the equation x^2-2x+5=48 ?

The solutions to the equation x^2-2x+5=48 are x=1+2sqrt(11),x=1-2sqrt(11)

Find the zeros of x^2-2x+5=48

The zeros of x^2-2x+5=48 are x=1+2sqrt(11),x=1-2sqrt(11)

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x^{2} - 2 x + 5 = 48

x = 1 + 211, x = 1 - 211

Decimal Notation

x = 7.63324 \dots, x = - 5.63324 \dots

Solution steps

x^{2} - 2 x + 5 = 48

Move

48

to the left side

x^{2} - 2 x - 43 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 43 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 43) = 411

x_{1, 2} = \frac{- ( - 2 ) \pm 4 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 11}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 4 11}{2 \cdot 1}

x = \frac{- ( - 2 ) + 4 11}{2 \cdot 1} : 1 + 211

x = \frac{- ( - 2 ) - 4 11}{2 \cdot 1} : 1 - 211

The solutions to the quadratic equation are:

x = 1 + 211, x = 1 - 211

9 y^{2} - 18 y + 9 = 0

3 (x + 8)^{2} = 5

(x + 8) (x - 4) - 2 (x - 8) (x - 4) = 24 (x - 8)

(6 x - 7)^{2} + 12 (6 x - 7) + 36 = 0

x^{2} + 5 x - 14 = - 8

What are the solutions to the equation x^2-2x+5=48 ?
The solutions to the equation x^2-2x+5=48 are x=1+2sqrt(11),x=1-2sqrt(11)
Find the zeros of x^2-2x+5=48
The zeros of x^2-2x+5=48 are x=1+2sqrt(11),x=1-2sqrt(11)