What are the solutions to the equation solvefor x,2x^2-3x-15=0 ?

The solutions to the equation solvefor x,2x^2-3x-15=0 are x=(3+sqrt(129))/4 ,x=(3-sqrt(129))/4

Find the zeros of solvefor x,2x^2-3x-15=0

The zeros of solvefor x,2x^2-3x-15=0 are x=(3+sqrt(129))/4 ,x=(3-sqrt(129))/4

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x, 2 x^{2} - 3 x - 15 = 0

x = \frac{3 + 129}{4}, x = \frac{3 - 129}{4}

Decimal Notation

x = 3.58945 \dots, x = - 2.08945 \dots

Solution steps

2 x^{2} - 3 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 15) = 129

x_{1, 2} = \frac{- ( - 3 ) \pm 129}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 129}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 129}{2 \cdot 2}

x = \frac{- ( - 3 ) + 129}{2 \cdot 2} : \frac{3 + 129}{4}

x = \frac{- ( - 3 ) - 129}{2 \cdot 2} : \frac{3 - 129}{4}

The solutions to the quadratic equation are:

x = \frac{3 + 129}{4}, x = \frac{3 - 129}{4}

- 7 x + x^{2} = 0

x^{2} - 8 x - 19 = 0

a x^{2} + x + a = 0

84 a^{2} + 76 a = 280

y, x + (y - 6)^{2} = 0

What are the solutions to the equation solvefor x,2x^2-3x-15=0 ?
The solutions to the equation solvefor x,2x^2-3x-15=0 are x=(3+sqrt(129))/4 ,x=(3-sqrt(129))/4
Find the zeros of solvefor x,2x^2-3x-15=0
The zeros of solvefor x,2x^2-3x-15=0 are x=(3+sqrt(129))/4 ,x=(3-sqrt(129))/4