What are the solutions to the equation (3x+7)^2=36 ?

The solutions to the equation (3x+7)^2=36 are x=-1/3 ,x=-13/3

Find the zeros of (3x+7)^2=36

The zeros of (3x+7)^2=36 are x=-1/3 ,x=-13/3

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(3 x + 7)^{2} = 36

x = - \frac{1}{3}, x = - \frac{13}{3}

Decimal Notation

x = - 0.33333 \dots, x = - 4.33333 \dots

Solution steps

(3 x + 7)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 7 = 36 : x = - \frac{1}{3}

Solve

3 x + 7 = - 36 : x = - \frac{13}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - \frac{13}{3}

- 5 x^{2} + 5 x + 3 = 0

(x - 1)^{2} + (x - 8)^{2} = x^{2}

3 x^{2} - 26 x + 2 = 0

x^{2} - 14 x + 16 = - 8

x^{2} + 6 x = - 25

What are the solutions to the equation (3x+7)^2=36 ?
The solutions to the equation (3x+7)^2=36 are x=-1/3 ,x=-13/3
Find the zeros of (3x+7)^2=36
The zeros of (3x+7)^2=36 are x=-1/3 ,x=-13/3