What are the solutions to the equation 36y^2-24y+85=0 ?

The solutions to the equation 36y^2-24y+85=0 are y= 1/3+i 3/2 ,y= 1/3-i 3/2

Find the zeros of 36y^2-24y+85=0

The zeros of 36y^2-24y+85=0 are y= 1/3+i 3/2 ,y= 1/3-i 3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

36 y^{2} - 24 y + 85 = 0

y = \frac{1}{3} + i \frac{3}{2}, y = \frac{1}{3} - i \frac{3}{2}

Solution steps

36 y^{2} - 24 y + 85 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 36 \cdot 85}{2 \cdot 36}

Simplify

(- 24)^{2} - 4 \cdot 36 \cdot 85 : 108 i

y_{1, 2} = \frac{- ( - 24 ) \pm 108 i}{2 \cdot 36}

Separate the solutions

y_{1} = \frac{- ( - 24 ) + 108 i}{2 \cdot 36}, y_{2} = \frac{- ( - 24 ) - 108 i}{2 \cdot 36}

y = \frac{- ( - 24 ) + 108 i}{2 \cdot 36} : \frac{1}{3} + i \frac{3}{2}

y = \frac{- ( - 24 ) - 108 i}{2 \cdot 36} : \frac{1}{3} - i \frac{3}{2}

The solutions to the quadratic equation are:

y = \frac{1}{3} + i \frac{3}{2}, y = \frac{1}{3} - i \frac{3}{2}

5 v^{2} - 20 v = 0

(n) = n^{2} - 4 n + 20

- x^{2} + 7 x = 11.25

w^{2} - 10 w

r^{2} + r - 4 = 0

What are the solutions to the equation 36y^2-24y+85=0 ?
The solutions to the equation 36y^2-24y+85=0 are y= 1/3+i 3/2 ,y= 1/3-i 3/2
Find the zeros of 36y^2-24y+85=0
The zeros of 36y^2-24y+85=0 are y= 1/3+i 3/2 ,y= 1/3-i 3/2